-15x^2=14x-8

Solution for -15x^2=14x-8 equation:

-15x^2=14x-8

We move all terms to the left:

-15x^2-(14x-8)=0

We get rid of parentheses

-15x^2-14x+8=0

a = -15; b = -14; c = +8;
Δ = b2-4ac
Δ = -142-4·(-15)·8
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-26}{2*-15}=\frac{-12}{-30}
=2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+26}{2*-15}=\frac{40}{-30}
=-1+1/3
$